-y^2+-3y=y+6

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Solution for -y^2+-3y=y+6 equation: 



-y^2+-3y=y+6

We move all terms to the left:

-y^2+-3y-(y+6)=0

We add all the numbers together, and all the variables

-1y^2-3y-(y+6)=0

We get rid of parentheses

-1y^2-3y-y-6=0

We add all the numbers together, and all the variables

-1y^2-4y-6=0

a = -1; b = -4; c = -6;
Δ = b2-4ac
Δ = -42-4·(-1)·(-6)
Δ = -8
Delta is less than zero, so there is no solution for the equation

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